Answer
$x=\frac{sin\left(\frac{1}{2}\right)+\pi}{3}$
Work Step by Step
$\arcsin(3x-\pi)=\frac{1}{2}$
$\sin(\arcsin(3x-\pi))=sin(\frac{1}{2})$
$3x-\pi=sin(\frac{1}{2})$
$3x=sin(\frac{1}{2})+\pi$
$x=\frac{sin\left(\frac{1}{2}\right)+\pi}{3}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.6 Exercises - Page 372: 33
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
