Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.6 Exercises - Page 372: 5

Answer

$θ=\frac{\pi}{3}$

Work Step by Step

$\arccos (\frac{1}{2})= \cos^{-1} (\frac{1}{2})$ $\cos^{-1} (\frac{1}{2}) = θ$ $\cos θ = \frac{1}{2}$ $θ=\frac{\pi}{3}$
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