Answer
$\frac{(e^x+1)^3}{3}+C$
Work Step by Step
$\int e^x(e^x+1)^2dx$
let $e^x+1=u$
$du=e^x$ $dx $
$\int e^x(e^x+1)^2dx$
$=\int u^2$ $du$
$=\frac{1}{3}u^3+C$
$=\frac{(e^x+1)^3}{3}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 354: 96
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