Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 354: 92



Work Step by Step

$\int(-4x^3)e^{-x^4}dx$ let $u=-x^4$ $(4x^3)dx=du$ $dx=-\frac{1}{4x^3}du$ $\int(-4x^3)e^{-x^4}dx$ $=\int e^u$ $du$ $=e^u+C$ $=e^{-x^4}+C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.