Answer
$e^{-x^4}+C$
Work Step by Step
$\int(-4x^3)e^{-x^4}dx$
let $u=-x^4$
$(4x^3)dx=du$
$dx=-\frac{1}{4x^3}du$
$\int(-4x^3)e^{-x^4}dx$
$=\int e^u$ $du$
$=e^u+C$
$=e^{-x^4}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 354: 92
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