Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises: 92

Answer

$e^{-x^4}+C$

Work Step by Step

$\int(-4x^3)e^{-x^4}dx$ let $u=-x^4$ $(4x^3)dx=du$ $dx=-\frac{1}{4x^3}du$ $\int(-4x^3)e^{-x^4}dx$ $=\int e^u$ $du$ $=e^u+C$ $=e^{-x^4}+C$
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