Answer
$\frac{1}{2}e^{2x-1}+C$
Work Step by Step
$\int e^{2x-1}dx$
let $u=2x-1$
$2dx=du$
$dx=\frac{1}{2}du$
$\int e^{2x-1}dx$
$=\frac{1}{2} \int e^u du$
$=\frac{1}{2}e^u+C$
$=\frac{1}{2}e^{2x-1}+C$
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