Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 354: 93



Work Step by Step

$\int e^{2x-1}dx$ let $u=2x-1$ $2dx=du$ $dx=\frac{1}{2}du$ $\int e^{2x-1}dx$ $=\frac{1}{2} \int e^u du$ $=\frac{1}{2}e^u+C$ $=\frac{1}{2}e^{2x-1}+C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.