Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 354: 91

Answer

$e^{5x}+C$

Work Step by Step

$\int 5e^{5x}dx$ let $5x=u$ $5dx=du$ $dx=\frac{1}{5}du$ $\int 5e^{5x}dx$ $=\int e^u$ $du$ $=e^u+C$ $=e^{5x}+C$
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