Answer
$\frac{1}{3}e^{x^3}+C$
Work Step by Step
$\int x^2e^{x^3}dx$
let $u=x^3$
$du=3x^2dx$
$dx=\frac{1}{3x^2}du$
$\int x^2e^{x^3}dx$
$\frac{1}{3} \int e^u du$
$=\frac{1}{3}e^u+C$
$=\frac{1}{3}e^{x^3}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 354: 95
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