Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises: 95

Answer

$\frac{1}{3}e^{x^3}+C$

Work Step by Step

$\int x^2e^{x^3}dx$ let $u=x^3$ $du=3x^2dx$ $dx=\frac{1}{3x^2}du$ $\int x^2e^{x^3}dx$ $\frac{1}{3} \int e^u du$ $=\frac{1}{3}e^u+C$ $=\frac{1}{3}e^{x^3}+C$
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