Answer
$-\frac{1}{3}e^{1-3x}+C$
Work Step by Step
$\int e^{1-3x}dx$
let $u=1-3x$
$du=-3dx$
$-\frac{1}{3}du=dx$
$\int e^{1-3x}dx$
$=-\frac{1}{3} \int e^u du$
$=-\frac{1}{3}e^u+C$
$=-\frac{1}{3}e^{1-3x}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.4 Exercises - Page 354: 94
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
