Answer
$\ln|\csc(e^{2x})+\cot(e^{2x})|)+C$
Work Step by Step
$\int e^{2x} csc(e^{2x})dx$
let $e^{2x}=u$
$2e^{2x}dx=du$
$\int e^{2x} csc(e^{2x})dx$
$=\frac{1}{2}\int csc(u)du$
$=\frac{1}{2}(-ln|csc(u)+cot(u)|)+C$
$=\frac{1}{2}(-ln|csc(e^{2x})+cot(e^{2x})|)+C$