Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - 6.6 Logarithmic And Other Functions Defined By Integrals - Exercises Set 6.6 - Page 460: 22

Answer

$\bf{True}$

Work Step by Step

Here, we have: $\int \dfrac{2x}{1+x^2} \ dx=\ln (1+x^2)+Constant(C)$ Also, $\int_1^{1+x^2} \dfrac{1}{t} \ dt+C=[\ln (t)]_1^{1+x^2}=\ln (1+x^2)+Constant(C)$ Hence, the given statement is $\bf{True}$.
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