Answer
Ans.$ ∆=1/2bcSinA$
Work Step by Step
Given:-ABC is the required triangle with side a, b, c
Prove:-$ ∆=1/2bcSinA$
In ∆ACD
$SinA=CD/AC$
$CD=bSinA$
We know that
$Area of triangle=1/2× base× height=1/2×CD×AB$
$∆=1/2bcSinA$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Appendix B - Trigonometry Review - Exercise Set B - Page A25: 59
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