Answer
$\int_{0}^{\pi} sin~x~dx = 2$
Work Step by Step
We can find the area under the graph:
$\int_{0}^{\pi} sin~x~dx$
$=-cos~x~\vert_{0}^{\pi}$
$=-cos(\pi)-[-cos(0)]$
$=-(-1)-(-1)$
$=1+1$
$=2$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 5 - Section 5.3 - The Fundamental Theorem of Calculus - 5.3 Exercises - Page 407: 61
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