Answer
$= \frac{15}{\ln 2} $
Work Step by Step
$\int^{4}_0 2^{s} ds$
$= \frac{2^{s}}{\ln 2} |^{4}_0$
$= [\frac{2^{4}}{\ln 2} ] - [\frac{2^{0}}{\ln 2} ]$
$= [\frac{16}{\ln 2} ] - [\frac{1}{\ln 2} ]$
$= \frac{16-1}{\ln 2} $
$= \frac{15}{\ln 2} $
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 5 - Section 5.3 - The Fundamental Theorem of Calculus - 5.3 Exercises - Page 407: 51
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