Answer
$-1$
Work Step by Step
$\displaystyle\int ^{0}_{\pi/2}\cos\theta d\theta=\sin\theta]^{0}_{\pi/2}=\sin 0-\sin \frac{\pi}{2}=0-1=-1$
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 5 - Section 5.3 - The Fundamental Theorem of Calculus - 5.3 Exercises - Page 407: 33
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