Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 726: 36


$x \approx -1.00$

Work Step by Step

RECALL: $\ln{e^a} = a$ Take the natural logarithm of both sides to obtain: $\ln{e^{1-8x}}=\ln{7957}$ Use the rule above to obtain: $1-8x=\ln{7957}$ Subtract $1$ on both sides to obtain: $-8x = -1+\ln{7957}$ Divide $-8$ on both sides of the equation to obtain: $x = \dfrac{-1+\ln{7957}}{-8}$ Use a scientific calculator to obtain: $x=-0.9977259154 \\x \approx -1.00$
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