Answer
$x \approx 1.69$
Work Step by Step
RECALL:
$\log_b{a^x}=x \cdot \log_b{a}$
Take the natural logarithm of both sides to obtain:
$\ln{19^x}=\ln{143}$
Use the rule above with $b=e$ to obtain:
$x \cdot \ln{19}=\ln{143}$
Divide $\ln{19}$ to both sides of the equation to obtain:
$x =\dfrac{\ln{143}}{\ln{19}}$
Use a scientific calculator to obtain:
$x=1.685497531
\\x \approx 1.69$
