Answer
$x \approx 1.76$
Work Step by Step
RECALL:
$\log_b{a^x}=x \cdot \log_b{a}$
Take the natural logarithm of both sides to obtain:
$\ln{5^x}=\ln{17}$
Use the rule above with $b=e$ to obtain:
$x \cdot \ln{5}=\ln{17}$
Divide $\ln{5}$ to both sides of the equation to obtain:
$x =\dfrac{\ln{17}}{\ln{5}}$
Use a scientific calculator to obtain:
$x=1.760374428
\\x \approx 1.76$
