## Intermediate Algebra for College Students (7th Edition)

$x \approx 1.76$
RECALL: $\log_b{a^x}=x \cdot \log_b{a}$ Take the natural logarithm of both sides to obtain: $\ln{5^x}=\ln{17}$ Use the rule above with $b=e$ to obtain: $x \cdot \ln{5}=\ln{17}$ Divide $\ln{5}$ to both sides of the equation to obtain: $x =\dfrac{\ln{17}}{\ln{5}}$ Use a scientific calculator to obtain: $x=1.760374428 \\x \approx 1.76$