Intermediate Algebra for College Students (7th Edition)

$x \approx 0.59$
RECALL: $\log{10^x}=x$ Take the common logarithm of both sides to obtain: $\log{10^x}=\log{3.91}$ Use the rule above to obtain: $x=\log{3.91}$ Use a scientific calculator to obtain: $x=0.5921767574 \\x \approx 0.59$