Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set: 15

Answer

$5$

Work Step by Step

Note that $\sqrt{6} = 6^{\frac{1}{2}}$. Write $\sqrt{6}$ as $6^{\frac{1}{2}}$ to obtain: $6^{\frac{x-3}{4}}=6^{\frac{1}{2}}$ Use the rule $a^m=a^n \longrightarrow m=n$ to obtain: $\dfrac{x-3}{4} = \dfrac{1}{2}$ Cross-multiply to obtain: $2(x-3) = 4(1) \\2x-6=4$ Add 6 on both sides of the equation to obtain: $2x=10$ Divide 2 on both sides of the equation to obtain: $x = 5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.