Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 726: 20

Answer

$x \approx -0.19$

Work Step by Step

RECALL: $\ln{e^x} = x$ Take the natural logarithm of both sides to obtain: $\ln{(e^x)}=\ln{0.83}$ Use the rule above to obtain: $\ln{(e^x)}=\ln{0.83} \\x = \ln{0.83}$ Use a scientific calculator to obtain: $x =-0.1863295782 \\x\approx -0.19$
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