Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Review Exercises - Page 657: 4

Answer

{$4 \pm 3\sqrt {2}$}

Work Step by Step

Given: $(x-4)^2=18$ Take the common terms out. $(x-4)=\pm \sqrt {18}$ This can be written as: $x=4 \pm 3\sqrt {2}$ Hence, $x=${$4 \pm 3\sqrt {2}$}
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