Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Review Exercises - Page 657: 23

Answer

$x=4$ or $x=-4$.

Work Step by Step

$x^2-16=x^2+4x-4x-16=x(x+4)-4(x+4)=(x+4)(x-4)$ Thus $x=4$ or $x=-4$.
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