#### Answer

{$\pm \dfrac{\sqrt{6}}{3}$}

#### Work Step by Step

Given: $3x^2-2=0$
Take the common terms out.
$(x^2-\dfrac{2}{3})=0$
This can be written as: $[x^2-(\sqrt{\dfrac{2}{3}})^2]=0$
$(x-\sqrt{\dfrac{2}{3}})(x+\sqrt{\dfrac{2}{3}})=0$
or,$(x-\dfrac{\sqrt{6}}{3})(x+\dfrac{\sqrt{6}}{3})=0$
Thus, $x=\pm \dfrac{\sqrt{6}}{3} $
Hence, $x=${$\pm \dfrac{\sqrt{6}}{3}$}