#### Answer

$x=4$ or $x=-\frac{2}{3}$.

#### Work Step by Step

$3x^2-10x-8=3x^2-12x+2x-8=3x(x-4)+2(x-4)=(x-4)(3x+2)=0$
Thus $x=4$ or $x=-\frac{2}{3}$.

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ISBN 10:
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ISBN 13:
978-0-13417-894-3

$x=4$ or $x=-\frac{2}{3}$.

$3x^2-10x-8=3x^2-12x+2x-8=3x(x-4)+2(x-4)=(x-4)(3x+2)=0$
Thus $x=4$ or $x=-\frac{2}{3}$.

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