Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Review Exercises - Page 657: 2

Answer

{$\pm 5\sqrt 2)$}

Work Step by Step

Given: $3x^2-150=0$ Take the common terms out. $3(x^2-50)=0$ This can be written as: $[x^2-(5\sqrt{2})^2]=0$ $(x-5\sqrt 2)(x+5\sqrt 2)=0$ Thus, $x=\pm 5\sqrt 2 $ Hence, $x=${$\pm 5\sqrt 2)$}
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