Answer
{$\pm 8$}
Work Step by Step
Given: $2x^2-3=125$
This implies $2x^2-128=0$
Take the common terms out.
$2(x^2-64)=0$
This can be written as: $(x^2-8^2)=0$
$(x+8)(x-8)=0$
Thus, $x=\pm 8 $
Hence, $x=${$\pm 8$}
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 8 - Review Exercises - Page 657: 1
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