Answer
$\{3-2\sqrt 2,3+2\sqrt 2\}$
Work Step by Step
Factor the left side as a difference of squares and determine the solutions:
$$\begin{align*}
(x-3)^2-(2\sqrt 2)^2&=0\\
(x-3-2\sqrt 2)(x-2+2\sqrt 2)&=0\\
x-3-2\sqrt 2=0&\text{ or }x-3+2\sqrt 2=0\\
x=3+2\sqrt 2&\text{ or }x=3-2\sqrt 2.
\end{align*}$$
The solution set of the equation is:
$$\{3-2\sqrt 2,3+2\sqrt 2\}.$$
