## Intermediate Algebra for College Students (7th Edition)

$x = \frac{1}{2}$ or $x = -4$
$(2x + 3)(x + 2) = 10$ Simplify the equation. $2x^2+5x+6=10$ Subtract $10$ to both sides. $2x^2+7x+6-10=10-10$ $2x^2+7x-4=0$ Use the quadratic formula: $x = \frac{-b±\sqrt{b^2-4ac}}{2a}$ $a=2$, $b=7$, $c=-4$ $x = \frac{-7±\sqrt{7^2-(4⋅2⋅-4)}}{(2⋅2)}$ $x = \frac{-7±\sqrt{49-(-32)}}{4}$ $x = \frac{-7±\sqrt{81}}{4}$ $x = \frac{-7±9}{4}$ $x = \frac{2}{4}$ or $x = \frac{-16}{4}$ $x = \frac{1}{2}$ or $x = -4$