Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Mid-Chapter Check Point - Page 629: 7

Answer

$x=±\sqrt{13}i$

Work Step by Step

$2x^2 + 26 = 0$ Subtract $26$ to both sides. $2x^2 + 26-26 = 0-26$ $2x^2 = -26$ Divide both sides $2$. $\frac{2x^2}{2} = \frac{-26}{2}$ $x^2 = -13$ $x=±\sqrt{-13}$ $x=±\sqrt{13}i$
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