Answer
$x = \frac{3±\sqrt{15}}{3}$
Work Step by Step
$3x^2 - 6x - 2 = 0$
Use the quadratic formula: $x = \frac{-b±\sqrt{b^2-4ac}}{2a}$
$a=3$, $b=-6$, $c=-2$
$x = \frac{-(-6)±\sqrt{(-6)^2-(4⋅3⋅-2)}}{2⋅3}$
$x = \frac{6±\sqrt{36-(-24)}}{6}$
$x = \frac{6±\sqrt{60}}{6}$
$x = \frac{6±\sqrt{4⋅15}}{6}$
$x = \frac{6±2\sqrt{15}}{6}$
Simplify.
$x = \frac{3±\sqrt{15}}{3}$
