Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Mid-Chapter Check Point - Page 629: 6

Answer

$x = \frac{5±\sqrt{7}i}{2}$

Work Step by Step

$x^2 - 5x + 8 = 0$ Use the quadratic formula: $x = \frac{-b±\sqrt{b^2-4ac}}{2a}$ $a=1$, $b=-5$, $c=8$ $x = \frac{-(-5)±\sqrt{(-5)^2-(4⋅1⋅8)}}{(2⋅1)}$ $x = \frac{5±\sqrt{25-32}}{2}$ $x = \frac{5±\sqrt{-7}}{2}$ $x = \frac{5±\sqrt{7}i}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.