Answer
$x=\sqrt{7}-3$ or $x=-\sqrt{7}-3$
Work Step by Step
$x^2 + 6x = -2$
Complete the square by adding $(\frac{6}{2})^2=9$ on both sides
$x^2 + 6x +9= -2+9$
$(x^2 +3)^2= 7$
$x +3= ±\sqrt{7}$
$x= ±\sqrt{7}-3$
$x=\sqrt{7}-3$ or $x=-\sqrt{7}-3$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 8 - Mid-Chapter Check Point - Page 629: 4
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