Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Mid-Chapter Check Point - Page 629: 5

Answer

$x = \frac{±6\sqrt {5}}{{5}}$

Work Step by Step

$5x^2 + 1 = 37$ Subtract $1$ to both sides. $5x^2 + 1 -1= 37-1$ $5x^2 = 36$ Divide both sides by $5$. Thus, the equation becomes: $x^2 = \frac{36}{5}$ Get the square root of both sides. $\sqrt {x^2} = \sqrt {\frac{36}{5}}$ $x = \frac{±6}{\sqrt {5}}$ $x = \frac{±6\sqrt {5}}{{5}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.