## Intermediate Algebra for College Students (7th Edition)

$x = \frac{11}{3}$ or $x = -\frac{1}{3}$
$(3x - 5)^2=36$ Get the square root of both sides. $\sqrt {(3x - 5)^2}=\sqrt{36}$ $3x - 5=±6$ $3x-5 = 6$ or $3x-5 = -6$ Add $5$ to both sides. $3x-5 +5= 6+5$ or $3x-5+5 = -6+5$ $3x= 11$ or $3x=-1$ $x = \frac{11}{3}$ or $x = -\frac{1}{3}$