Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Mid-Chapter Check Point - Page 629: 1

Answer

$x = \frac{11}{3}$ or $x = -\frac{1}{3}$

Work Step by Step

$(3x - 5)^2=36$ Get the square root of both sides. $\sqrt {(3x - 5)^2}=\sqrt{36}$ $3x - 5=±6$ $3x-5 = 6$ or $3x-5 = -6$ Add $5$ to both sides. $3x-5 +5= 6+5$ or $3x-5+5 = -6+5$ $3x= 11$ or $3x=-1$ $x = \frac{11}{3}$ or $x = -\frac{1}{3}$
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