Answer
$13 $.
Work Step by Step
Write the terms as a product.
$=(3+2i)(3-2i)$
Use the special formula $(a+b)(a-b)=a^2-b^2$.
$=(3)^2-(2i)^2$
Use the product rule.
$=9-4i^2$
Use $i^2=-1$.
$=9+4$
Simplify.
$=13 $.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 571: 125
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