Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 571: 111

Answer

$10+10i$

Work Step by Step

The given functions are $f(x)=x-3i$ and $g(x)=4x+2i$. $\Rightarrow (fg)(x)=f(x)\cdot g(x)$ Substitute both functions. $\Rightarrow (fg)(x)=(x-3i)\cdot (4x+2i)$ Use the FOIL method. $\Rightarrow (fg)(x)=4x^2+2xi-12xi-6i^2$ Add like terms. $\Rightarrow (fg)(x)=4x^2-10xi-6i^2$ Use $i^2=-1$. $\Rightarrow (fg)(x)=4x^2-10xi+6$ Replace $x$ with $-1$. $\Rightarrow (fg)(-1)=4(-1)^2-10(-1)i+6$ Simplify. $\Rightarrow (fg)(-1)=4+10i+6$ Add like terms. $\Rightarrow (fg)(-1)=10+10i$
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