Answer
$(47+13i)$ volts.
Work Step by Step
$I=(4-5i)$ amperes and $R=(3+7i) \ ohms$.
The formula is
$\Rightarrow E=IR$.
Substitute the values.
$\Rightarrow E=(4-5i)(3+7i)$.
Use the FOIL method.
$\Rightarrow E=12+28i-15i-35i^2$.
Use $i^2=-1$.
$\Rightarrow E=12+28i-15i+35$.
Add like terms.
$\Rightarrow E=47+13i$.
Hence, the value of $E$ is $(47+13i)$ volts.
