Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 571: 123

Answer

$-6+10i$.

Work Step by Step

Write the terms as a product. $=(2i)(5+3i)$ Use the distributive property. $=(2i)(5)+(2i)(3i)$ Multiply. $=10i+6i^2$ Use $i^2=-1$. $=10i+6(-1)$ Simplify. $=10i-6$ $=-6+10i$.
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