## Intermediate Algebra for College Students (7th Edition)

$-3$
RECALL: $a^{\frac{1}{n}}=\sqrt[n]{a}$ $\sqrt [n] {a^{n}}=a$ With $n=4$, use the rules above to obtain: $-81^{\frac{1}{4}} \\=-(81^{\frac{1}{4}}) \\=-\sqrt[4]{81} \\ -\sqrt[4] {3^{4}} \\-3$