Intermediate Algebra for College Students (7th Edition)

Published by Pearson

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 521: 40

Answer

$\dfrac{1}{3}$

Work Step by Step

RECALL: (i) $a^{-\frac{m}{n}}=\dfrac{1}{a^{\frac{m}{n}}}$ (i) $a^{\frac{m}{n}}=\sqrt[n]{a^m}$ Use the rules above to obtain: $=\dfrac{1}{9^{\frac{1}{2}}} \\=\dfrac{1}{\sqrt{9}} \\=\dfrac{1}{3}$

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