Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 521: 18



Work Step by Step

$(a^m)^n=a^{mn}$ Thus $4^{\frac{5}{2}}-8^{\frac{2}{3}}=(2^2)^{\frac{5}{2}}-(2^3)^{\frac{2}{3}}=2^{2\cdot\frac{5}{2}}-2^{3\cdot\frac{2}{3}}=2^5-2^2=32-4=28$
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