Answer
$-2$
Work Step by Step
RECALL:
$a^{\frac{1}{n}}=\sqrt[n]{a}$
$\sqrt [n] {a^{n}}=a$
With $n=4$, use the rules above to obtain:
$-16^{\frac{1}{4}}
\\=-(16^{\frac{1}{4}})
\\=-\sqrt[4]{16}
\\=-\sqrt[4] {2^{4}}
\\=-2$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 521: 5
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