## Intermediate Algebra for College Students (7th Edition)

$(11x)^{\frac{1}{5}}$
RECALL: $\sqrt[n]{a}=a^{\frac{1}{n}}$ The given expression involves a fifth root, so $n=5$. Also, $a=11x$. Thus, $\sqrt[5]{11x}=(11x)^{\frac{1}{5}}$