## Intermediate Algebra for College Students (7th Edition)

$(xy^3)^{\frac{1}{7}}$
RECALL: $\sqrt[n]{a}=a^{\frac{1}{n}}$ For the given expression, $n=7$ and $a=xy^3$. Thus, $\sqrt[7]{xy^3}=(xy^3)^{\frac{1}{7}}$