Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 521: 36



Work Step by Step

RECALL: $(\sqrt[n]{a})^m=\left(a^{\frac{1}{n}}\right)^m=a^{\frac{m}{n}}$ For the given expression, $n=6$, $a=9x^2y$, and $m=5$. Thus, using the rule above gives: $\left(\sqrt[6]{9x^2y}\right)^5=\left((9x^2y)^{\frac{1}{6}}\right)^5=(9x^2y)^{\frac{5}{6}}$
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