Answer
$=1$.
Work Step by Step
The given expression is
$=27^{\frac{2}{3}}+(-32)^{\frac{3}{5}}$
Factor each term:
$=(3^3)^{\frac{2}{3}}+(-2^5)^{\frac{3}{5}}$
To raise a power to a power, multiply exponents.
$=3^{3\cdot \frac{2}{3}}+(-2)^{5\cdot \frac{3}{5}}$
Simplify.
$=3^{2}+(-2)^{3}$
$=9-8$
$=1$.
