Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Mid-Chapter Check Point - Page 541: 1

Answer

$=13$.

Work Step by Step

The given expression is $=\sqrt{100}-\sqrt[3] {-27}$ Factor the radicands: $=\sqrt{25\cdot 4}-\sqrt[3] {-27}$ $=\sqrt{5^2\cdot 2^2}-\sqrt[3] {-3^3}$ $=\sqrt{(10)^2}-\sqrt[3] {(-3)^3}$ Rewrite as an exponential expression. $=(10)^{\frac{2}{2}}-(-3)^{\frac{3}{3}}$ Simplify. $=(10)^1-(-3)^1$ $=10+3$ $=13$.
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