Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Mid-Chapter Check Point - Page 541: 11

Answer

$2\sqrt [3]{ 10}$.

Work Step by Step

The given expression is $=\frac{\sqrt [3]{160}}{\sqrt [3]{2}}$ Divide the radicands and retain the common index. $=\sqrt [3]{\frac{160}{2}}$ Divide factors in the radicand. $=\sqrt [3]{80}$ Factor the radicands: $=\sqrt [3]{2^3\cdot 10}$ Simplify. $=2\sqrt [3]{ 10}$.
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