Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Mid-Chapter Check Point - Page 541: 15

Answer

$(x-2)\sqrt[7] {(x-2)^{2} }$.

Work Step by Step

The given expression is $=\sqrt[7] {(x-2)^3}\cdot \sqrt[7] {(x-2)^6}$ Use the product rule. $=\sqrt[7] {(x-2)^3\cdot(x-2)^6 }$ Use power rule. $=\sqrt[7] {(x-2)^{3+6} }$ Simplify. $=\sqrt[7] {(x-2)^{9} }$ Factor as a power of $7$. $=\sqrt[7] {(x-2)^{7+2} }$ Use power rule. $=\sqrt[7] {(x-2)^{7}(x-2)^{2} }$ Simplify. $=(x-2)\sqrt[7] {(x-2)^{2} }$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.