Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Mid-Chapter Check Point - Page 541: 4

Answer

$12x\sqrt[3] { 2 x}$.

Work Step by Step

The given expression is $=(3\sqrt[3] {4x^2})(2\sqrt[3] {4x^2})$ Use the product rule. $=6\sqrt[3] {4x^2\cdot 4x^2}$ $=6\sqrt[3] {16x^4}$ $=6\sqrt[3] {2^3\cdot 2x^3\cdot x}$ $=6\sqrt[3] {2^3\cdot 2x^3\cdot x}$ $=6\cdot 2x\sqrt[3] { 2 x}$ Simplify. $=12x\sqrt[3] { 2 x}$.
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